In article " Receptacle Branch Circuit Design Calculations – Part Three ", I stated that a Receptacle in dwelling units may serve one of the following loads:
 Generaluse Receptacle Loads,
 Small appliance Loads,
 Laundry Load,
 Cloth dryer Load,
 Household cooking appliances load,
 Fastenedinplace Appliance loads,
 Heating and air conditioning loads,
 Motor loads.
I explained the first four types in the following articles:
In the following paragraphs, I will explain Where and how to distribute each load outlets in a dwelling building as per NEC code.
You can review the following articles for more information:
5 Household cooking appliances load
5.1 Applied NEC Rules for Household cooking appliances load
There are many NEC rules that control the location and load of Household cooking appliances including:
5.2 Calculation of Household Cooking Appliances load
A For feeder and service calculation purposes
First: As per NEC Standard calculation method
We have (5) cases for using table 220.55 as follows:
The service load for one household cooking appliance is permitted to be computed by using either the nameplate rating of the appliance or Table 220.55.
In this case, Procedure for calculating the service demand load will be as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances = 1
Step#2: Follow the row (for number of appliances = 1) across to the appropriate column A, B or C.
Step#3: Service demand load calculation
Example#1:
What is the service demand load for a 3kW, wallmounted oven?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column A
Step#3: In accordance with Column A, The demand factor percent = 80%
So, the service demand Load= 3 KW X 0.8 = 2.4 KW
Case#2: group of Appliances with equal (same) ratings not over 12 KW
The procedure is the same as in case#1 for individual Appliance as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances,
Step#2: Follow the row (for number of appliances given) across to the appropriate column A, B or C.
Step#3: Service demand load calculation
Example#4:
A 10unit apartment building will have a 12kW range in each apartment. What is the service demand load these ranges?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=10.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=10, the maximum service demand will be 25 kW
Example#5:
What is the service demand load for 40 wallmounted ovens with same 3kW rating?
Step#1: Look in the left column of Table 220.55 for the number of appliances=25.
Step#2: Follow the row across to the appropriate column which will be Column A
Step#3: In accordance with Column A, The demand factor percent = 30%
So, the service demand Load= Number of Appliances x Load of Individual appliance x Demand factor = 25 x 3 KW X 0.3 = 22.5 KW
Example#6:
What is the service demand load for 40 ranges with same 10kW rating?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=40.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=40, the maximum service demand will be 15 kW + 1 kW for each range.
So, the maximum service demand = 15 kW + number of appliances = 15 + 40 = 55 KW
Example#7:
What is the service demand load for 60 ranges with same 12kW rating?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=60.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=60, the maximum service demand will be 15 kW + 0.75 kW for each range.
So, the maximum service demand = 25 kW + number of appliances X 0.75 KW = 25+ 60 X 0.75 = 70 KW
Case#3: group of Appliances with unequal ratings not over 12 KW
The procedure is the same as in case#2 for individual Appliance but Steps#1, 2 and 3 will be repeated for each Appliance as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances,
Step#2: Follow the row (for number of appliances given) across to the appropriate column A, B or C.
Step#3: Service demand load calculation
Step#4: Sum individual service demand loads to get the total service demand load.
Example#8:
What is the service demand load for ten 2.5kW ovens, ten 3kW ovens, ten 5kW cooktops and ten 6kW cooktops?
Solution:
First: for 20 units that are within the limits of Column A
Step#1:The 2.5kW ovens have a rating = 10 × 2½ = 25 KW.
The 3kW ovens have a rating = 10 × 3 = 30KW.
The ovens have a total rating = 25 + 30 = 55 KW
Step#2: Because 20 ovens fall within the limits of Column A, the demand factor is 35 %.
Step#3: The calculated demand for the ovens = 55 × 35% = 19.25 KW
Second: for 20 units that are within the limits of Column B
Step#1: The 5kW cooktops have a rating = 10 × 5 = 50 KW
The 6kW cooktops have a rating = 10 × 6 = 60 KW
The cooktops have a total rating = 50 + 60 = 110 KW
Step#2: Because 20 ovens fall within the limits of Column B, the demand factor is 28 %.
Step#3: The calculated demand for the cooktops = 110 × 28% = 30.8 KW
Step#4: Now add the results to find the total demand load = 19.25 + 30.8 = 50.05 KW
Example#9:
What is the service demand load for five 3.5kW wallmounted ovens, five 5kW countermounted cooking units and ten 8kW ranges?
Solution:
Step#1: the total number of units (5 + 5 + 10 = 20).
Step#2: Because none of the appliances are rated less than 3½ kW or more than 8¾ kW, the demand factor will come from Column B.
So, the demand factor percent across from 20 units (28 percent).
Step#3:
The ovens have a total rating of 17½ kW = 5 × 3.5 = 17.5KW
The cooktops have total rating of 25 kW = 5 × 5 = 25 KW
The ranges have a total rating of 80 kW = 10 × 8 = 80 KW
Step#4:
The combined rating of all the appliances = 17.5 + 25 + 80 = 122.5 KW
The service demand load = 122.5 KW × 28% = 34.3 KW
Optional Calculation for Cases# 2 and 3 and appliances ratings Over 1 3 ⁄4 kW through 8 3⁄4 kW
What is the service demand load for 6 ranges with same 8kW rating?
Solution:
Using the optional method for household cooking appliances with ratings Over 1 3 ⁄4 kW through 8 3⁄4 kW
Step#1: Calculate the service demand Load for such appliances whether falling under Column A or B
In accordance with column B, the demand factor for 6 nos. appliances is 43% , so the service demand load = 6 x 8 x 0.43 = 20.64 KW
Step#2: Calculate the same using Column C,
In accordance with column C, for 6 nos. appliances, the Max. demand load = 21 KW
Step#3: Choose the lowest value between steps# 1 and 2 to be the service demand Load.
So, the service demand Load = the lowest value between steps# 1 and 2 = 20.64 KW
Case#4: Individual / group of Ranges with equal (same) ratings Over 12 kW through 27 KW
For ranges individually rated more than 12 kW but not more than 27 kW, the calculation procedure will be as follows:
Step#1: Calculate the maximum demand for the given number of ranges in Column C.
Step#2: Find the KW Load increase over 12 KW = KW of one range – 12
Step#3: Find the increased demand amount = Step#1 x Step#2 x 0.05
Step#4: Total service demand load= step#1 +step#3
Example#11:
What is the service demand load for one 14kW household electric range?
Solution: Step#1: the maximum demand for one ranges in Column C = 8 KW
Step#2: Load increase over 12 KW = 14 – 12 = 2 KW
Step#3: the increased demand amount = Step#1 x Step#2 x 0.05 = 8x2x0.05 = 0.8 KW
Step#4: Total service demand load= step#1 +step#3 = 8 + 0.8 = 8.8 kW
Case#5: group of Ranges with unequal ratings Over 8 3⁄4 kW through 27 kW
For ranges individually rated more than 8 3⁄4 kW and of different ratings, but none exceeding 27 kW, the calculation procedure will be as follows:
Step#1: Calculate the maximum demand for the given number of ranges in Column C.
Step#2: Calculate the Average Rating = sum of all appliances rating (using 12 kW for any range rated less than 12 kW) / number of appliances
Step#3: Find the KW Load increase over 12 KW = average load KW – 12
Step#4: Find the increased demand amount = Step#1 x Step#3 x 0.05
Step#5: Total service demand load= step#1 +step#4
Example#12:
What is the service demand load for five 13kW, five 15kW and five 17kW household electric ranges?
Solution:
Step#1: the maximum demand for 15 ranges in Column C = 30 KW
Step#2: the Average Rating = [(5 × 13) + (5 × 15) + (5 × 17) / 15 = 15 KW
Step#3: Load increase over 12 KW = 15 – 12 = 3 KW
Step#4: the increased demand amount = Step#1 x Step#3 x 0.05 = 30x3x0.05 = 4.5 KW
Step#5: Total service demand load= step#1 +step#3 = 30 + 4.5 = 34.5 kW
Example#13:What is the service demand load for eight 9kW, six 13kW and six 15kW household electric ranges?
Solution:
Step#1: the maximum demand for 20 ranges in Column C = 35 KW
Step#2: the Average Rating = [(8 × 12) + (6× 13) + (6 × 15) / 20 = 13.2 KW
Notes:
Step#3: Load increase over 12 KW = 13 – 12 = 1 KW
Step#4: the increased demand amount = Step#1 x Step#3 x 0.05 = 35x1x0.05 = 1.75 KW
Step#5: Total service demand load= step#1 +step#3 = 35 + 1.75 = 36.75 kW
Second: As per NEC Optional calculation method:
Example#14:
A multifamily dwelling has 20 dwelling units, Onehalf of the dwelling units are equipped with electric ranges not exceeding 12 kW each and other half of ranges are gas ranges. What is the service demand load for these ranges?
Solution:
1 Calculated Load for Each Dwelling Unit
In accordance with column C in table 220.55, Max. demand load for One Electric range = 8KW
2 Calculate the service demand load
Step#1: Look in the left column of Table 220.55 for the number of appliances=10.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: The maximum service demand load = 25 KW
B For branch circuit requirements calculation
1 Determining BranchCircuit Load
Household cooking appliances branch circuit conductor ampacity & size and overcurrent protection will be explained in coming articles, however you can review the calculation for maximum number of allowable receptacles on a branch circuit which was discussed before in previous article " Receptacle Branch Circuit Design Calculations – Part Three ".
5.4 How to specify the required Type and Rating of receptacles for household cooking appliances?
A Range Receptacle Rating
The ampere rating of a range receptacle shall be permitted to be based on a single range demand load as specified in Table 220.55.
B GFCI Type
As I explained in Rule#4 that a Receptacle outlet connected to small appliance branch circuits is permitted to serve Supplemental equipment and lighting on gasfired ranges, ovens, or countermounted cooking units.
As per NEC section 210.8 A (6), where the receptacles are installed to serve the countertop kitchen appliances (countermounted cooking units) around a kitchen sink must be GFCI Type. See below image.
But the receptacle serves Supplemental equipment and lighting on gasfired ranges and ovens will not be GFCI type as in above image.
According to 406.5(E), receptacles installed to serve countertops cannot be installed in the countertop in the faceup position because liquid, dirt, and other foreign material can enter the receptacle
C TamperResistant type
TamperResistant receptacles are intended to increase safety for children.
The Receptacles in the following locations shall not be required to be tamperresistant:
In the next article, I will explain Receptacle branch circuits that serve other types of loads. Please, keep following.
You can review the following articles for more information:
5 Household cooking appliances load
Definition:
Cooking Unit, CounterMounted is a cooking appliance designed for mounting in or on a counter and consisting of one or more heating elements, internal wiring, and builtin or mountable controls.(see below image)

 Wallmounted ovens and countermounted cooking units complete shall be permitted to be permanently connected or, only for ease in servicing or for installation, cordandplugconnected.
 A portable cooking appliance (e.g., cordandplugconnected microwave oven or hot plate) is not a permanent cooking facility.
5.1 Applied NEC Rules for Household cooking appliances load
There are many NEC rules that control the location and load of Household cooking appliances including:
 NEC section 220.53
 210.18 Guest Rooms and Guest Suites  dwelling units
 210.19 (A) (3) Minimum Ampacity and Size of conductors for Branch Circuits Not More Than 600 Volts supplying Household Ranges and Cooking Appliances
 210.50 General (C) Appliance Receptacle Outlets
 210.52(B) Small Appliances (2) No Other Outlets Exception No. 2
 210.23 Permissible Loads (C) 40 and 50Ampere Branch Circuits
 220.55 Electric Ranges and Other Cooking Appliances — Dwelling Unit(s)
Rule#1: Location of receptacle outlet used for Electric Ranges
Appliance receptacle
outlets installed in a dwelling unit for specific appliances, such as laundry
equipment, shall be installed within 1.8 m (6 ft) of the intended location of
the appliance.
Receptacle outlets for Wallmounted ovens and
countermounted cooking units shall be located on or above, but
not more than 500 mm (20 in.) above, the countertop.

Rule#2: Guest Rooms and
Guest Suites in dwelling units and that are provided with permanent provisions
for cooking(see below image)
Guest rooms and guest suites that are provided
with permanent provisions for cooking shall have branch circuits installed in
the cooking area to meet the all of the requirements for dwelling units
contained in Parts I, II, and III of Article 210.

Important!!!
A portable cooking appliance (e.g.,
cordandplugconnected microwave oven or hot plate) is not a permanent
cooking facility.

Rule#3: Not
FastenedinPlace Appliances
As per NEC section 220.53, electric
ranges, clothes dryers, spaceheating equipment or air conditioning equipment
must not be included with the number of appliances that are fastened in place.
Also, All portable small Appliances for kitchen and others are not
FastenedinPlace Appliances.

Rule#4: Supplying Supplemental equipment and lighting
Receptacle outlets of small appliance branch circuits are permitted to
serve Supplemental equipment and lighting on gasfired ranges, ovens, or
countermounted cooking units.

Important!!!
In most dwellings the countertop receptacle outlets supply more of the
portable cooking appliances than the wall receptacles in the kitchen and
dining areas, hence the requirement for the counter areas to be supplied by
no fewer than two smallappliance branch circuits.

5.2 Calculation of Household Cooking Appliances load
A For feeder and service calculation purposes
First: As per NEC Standard calculation method
Rule#5: Code
Requirement for Household Cooking Appliances
Household Cooking Appliances (ranges, wall mounted ovens,
countermounted cooking appliances, etc.) are not required in a NEC load
calculation. We can skip the calculation of Household Cooking Appliances Load
if there are no cooking appliances rated over 1.75 KW.

Important!!!
Kilovoltamperes (kVA) shall be considered
equivalent to kilowatts (kW) for Electric Ranges and Other Cooking
Appliances.

Important!!!
When the
kilowatt rating fraction is 0.5 or more, it must be
rounded up to
the next whole kilowatt rating i.e. 14.5 KW up to
a 15
KW and When the fraction is less than 0.5, it can be dropped i.e. 14.4 KW
dropped to 14 KW.

Rule#6: calculating household
cooking appliances load in accordance with Table 220.55.
As per NEC section 220.55, The load for household
electric ranges, wallmounted ovens, countermounted cooking units, and other
household cooking appliances individually rated in excess of 1.75 kW shall be
permitted to be calculated in accordance with Table 220.55.

Important!!!
The
table
220.55 is not applicable for ranges rated more than 27 kW because
ranges rated more than 27 kW would not be considered household ranges.

We have (5) cases for using table 220.55 as follows:
Case#1: Individual Appliance not over 12 KW
The service load for one household cooking appliance is permitted to be computed by using either the nameplate rating of the appliance or Table 220.55.
In this case, Procedure for calculating the service demand load will be as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances = 1
Step#2: Follow the row (for number of appliances = 1) across to the appropriate column A, B or C.
 Column A is used where the rating of the appliance is less than 3½ kW
 Column B is used where the rating of the appliance is 3½ kW through 8¾ Kw
 Column C is used where the rating of the appliance not over 12kW.
Step#3: Service demand load calculation
 If Column A or B is used, Service demand load = Load of the Individual Appliance x Demand factor
 If Column C is used, Service demand load = Max. Demand Load in column C
Example#1:
12kW electric range will be installed in a onefamily dwelling, what is the service demand load for this range?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, a 12kW range has a maximum demand of 8 kW
Example#2:
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, a 12kW range has a maximum demand of 8 kW
Example#2:
What is the service demand load for a 9kW range?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, The maximum load required for one 9kW range when calculating a service or feeder is 8 kW.
Example#3:
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, The maximum load required for one 9kW range when calculating a service or feeder is 8 kW.
Example#3:
What is the service demand load for a 3kW, wallmounted oven?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=1.
Step#2: Follow the row across to the appropriate column which will be Column A
Step#3: In accordance with Column A, The demand factor percent = 80%
So, the service demand Load= 3 KW X 0.8 = 2.4 KW
Case#2: group of Appliances with equal (same) ratings not over 12 KW
The procedure is the same as in case#1 for individual Appliance as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances,
Step#2: Follow the row (for number of appliances given) across to the appropriate column A, B or C.
 Column A is used where the rating of the appliances (have same rating) is less than 3½ kW.
 Column B is used where the rating of the appliances (have same rating) is 3½ kW through 8¾ KW
 Column C is used where the rating of the appliances (have same rating) is not over 12kW.
Step#3: Service demand load calculation
 If Column A or B is used, Service demand load = Number of Appliances x Load of Individual appliance x Demand factor
 If Column C is used, Service demand load = Max. Demand Load in column C
Example#4:
A 10unit apartment building will have a 12kW range in each apartment. What is the service demand load these ranges?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=10.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=10, the maximum service demand will be 25 kW
Example#5:
What is the service demand load for 40 wallmounted ovens with same 3kW rating?
Solution:
Step#2: Follow the row across to the appropriate column which will be Column A
Step#3: In accordance with Column A, The demand factor percent = 30%
So, the service demand Load= Number of Appliances x Load of Individual appliance x Demand factor = 25 x 3 KW X 0.3 = 22.5 KW
Example#6:
What is the service demand load for 40 ranges with same 10kW rating?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=40.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=40, the maximum service demand will be 15 kW + 1 kW for each range.
So, the maximum service demand = 15 kW + number of appliances = 15 + 40 = 55 KW
Example#7:
What is the service demand load for 60 ranges with same 12kW rating?
Solution:
Step#1: Look in the left column of Table 220.55 for the number of appliances=60.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: In accordance with Column C, for the number of appliances=60, the maximum service demand will be 15 kW + 0.75 kW for each range.
So, the maximum service demand = 25 kW + number of appliances X 0.75 KW = 25+ 60 X 0.75 = 70 KW
Case#3: group of Appliances with unequal ratings not over 12 KW
The procedure is the same as in case#2 for individual Appliance but Steps#1, 2 and 3 will be repeated for each Appliance as follows:
Step#1: Look in Left column of Table 220.55 for the number of appliances,
Step#2: Follow the row (for number of appliances given) across to the appropriate column A, B or C.
 Column A is used where the rating of the appliances (have same rating) is less than 3½ kW.
 Column B is used where the rating of the appliances (have same rating) is 3½ kW through 8¾ KW
 Column C is used where the rating of the appliances (have same rating) is not over 12kW.
Step#3: Service demand load calculation
 If Column A or B is used, Service demand load = Number of Appliances x Load of Individual appliance x Demand factor
 If Column C is used, Service demand load = Max. Demand Load in column C
Step#4: Sum individual service demand loads to get the total service demand load.
Example#8:
What is the service demand load for ten 2.5kW ovens, ten 3kW ovens, ten 5kW cooktops and ten 6kW cooktops?
Solution:
First: for 20 units that are within the limits of Column A
Step#1:The 2.5kW ovens have a rating = 10 × 2½ = 25 KW.
The 3kW ovens have a rating = 10 × 3 = 30KW.
The ovens have a total rating = 25 + 30 = 55 KW
Step#2: Because 20 ovens fall within the limits of Column A, the demand factor is 35 %.
Step#3: The calculated demand for the ovens = 55 × 35% = 19.25 KW
Second: for 20 units that are within the limits of Column B
Step#1: The 5kW cooktops have a rating = 10 × 5 = 50 KW
The 6kW cooktops have a rating = 10 × 6 = 60 KW
The cooktops have a total rating = 50 + 60 = 110 KW
Step#2: Because 20 ovens fall within the limits of Column B, the demand factor is 28 %.
Step#3: The calculated demand for the cooktops = 110 × 28% = 30.8 KW
Step#4: Now add the results to find the total demand load = 19.25 + 30.8 = 50.05 KW
Example#9:
What is the service demand load for five 3.5kW wallmounted ovens, five 5kW countermounted cooking units and ten 8kW ranges?
Solution:
Step#1: the total number of units (5 + 5 + 10 = 20).
Step#2: Because none of the appliances are rated less than 3½ kW or more than 8¾ kW, the demand factor will come from Column B.
So, the demand factor percent across from 20 units (28 percent).
Step#3:
The ovens have a total rating of 17½ kW = 5 × 3.5 = 17.5KW
The cooktops have total rating of 25 kW = 5 × 5 = 25 KW
The ranges have a total rating of 80 kW = 10 × 8 = 80 KW
Step#4:
The combined rating of all the appliances = 17.5 + 25 + 80 = 122.5 KW
The service demand load = 122.5 KW × 28% = 34.3 KW
Optional Calculation for Cases# 2 and 3 and appliances ratings Over 1 3 ⁄4 kW through 8 3⁄4 kW
If appliances Ratings falling under Column A or B and C (ratings Over 1 3 ⁄4 kW through 8 3⁄4 kW), the calculation procedure will be as follows:
Step#1: Calculate the service demand Load for such appliances whether falling under Column A or B
Step#2: Calculate the same using Column C,
Step#3: Choose the lowest value between steps# 1 and 2 to be the service demand Load.
Example#10:
Step#1: Calculate the service demand Load for such appliances whether falling under Column A or B
Step#2: Calculate the same using Column C,
Step#3: Choose the lowest value between steps# 1 and 2 to be the service demand Load.
Example#10:
What is the service demand load for 6 ranges with same 8kW rating?
Solution:
Using the optional method for household cooking appliances with ratings Over 1 3 ⁄4 kW through 8 3⁄4 kW
Step#1: Calculate the service demand Load for such appliances whether falling under Column A or B
In accordance with column B, the demand factor for 6 nos. appliances is 43% , so the service demand load = 6 x 8 x 0.43 = 20.64 KW
Step#2: Calculate the same using Column C,
In accordance with column C, for 6 nos. appliances, the Max. demand load = 21 KW
Step#3: Choose the lowest value between steps# 1 and 2 to be the service demand Load.
So, the service demand Load = the lowest value between steps# 1 and 2 = 20.64 KW
Case#4: Individual / group of Ranges with equal (same) ratings Over 12 kW through 27 KW
For ranges individually rated more than 12 kW but not more than 27 kW, the calculation procedure will be as follows:
Step#1: Calculate the maximum demand for the given number of ranges in Column C.
Step#2: Find the KW Load increase over 12 KW = KW of one range – 12
Step#3: Find the increased demand amount = Step#1 x Step#2 x 0.05
Step#4: Total service demand load= step#1 +step#3
Example#11:
What is the service demand load for one 14kW household electric range?
Solution: Step#1: the maximum demand for one ranges in Column C = 8 KW
Step#2: Load increase over 12 KW = 14 – 12 = 2 KW
Step#3: the increased demand amount = Step#1 x Step#2 x 0.05 = 8x2x0.05 = 0.8 KW
Step#4: Total service demand load= step#1 +step#3 = 8 + 0.8 = 8.8 kW
Case#5: group of Ranges with unequal ratings Over 8 3⁄4 kW through 27 kW
For ranges individually rated more than 8 3⁄4 kW and of different ratings, but none exceeding 27 kW, the calculation procedure will be as follows:
Step#1: Calculate the maximum demand for the given number of ranges in Column C.
Step#2: Calculate the Average Rating = sum of all appliances rating (using 12 kW for any range rated less than 12 kW) / number of appliances
Step#3: Find the KW Load increase over 12 KW = average load KW – 12
Step#4: Find the increased demand amount = Step#1 x Step#3 x 0.05
Step#5: Total service demand load= step#1 +step#4
Example#12:
What is the service demand load for five 13kW, five 15kW and five 17kW household electric ranges?
Solution:
Step#1: the maximum demand for 15 ranges in Column C = 30 KW
Step#2: the Average Rating = [(5 × 13) + (5 × 15) + (5 × 17) / 15 = 15 KW
Step#3: Load increase over 12 KW = 15 – 12 = 3 KW
Step#4: the increased demand amount = Step#1 x Step#3 x 0.05 = 30x3x0.05 = 4.5 KW
Step#5: Total service demand load= step#1 +step#3 = 30 + 4.5 = 34.5 kW
Example#13:What is the service demand load for eight 9kW, six 13kW and six 15kW household electric ranges?
Solution:
Step#1: the maximum demand for 20 ranges in Column C = 35 KW
Step#2: the Average Rating = [(8 × 12) + (6× 13) + (6 × 15) / 20 = 13.2 KW
Notes:
 Use 12 kW for any range rated less than 12 kW
 13.2 KW will be dropped to 13 KW
Step#3: Load increase over 12 KW = 13 – 12 = 1 KW
Step#4: the increased demand amount = Step#1 x Step#3 x 0.05 = 35x1x0.05 = 1.75 KW
Step#5: Total service demand load= step#1 +step#3 = 35 + 1.75 = 36.75 kW
Second: As per NEC Optional calculation method:
Rule#7: Application of NEC Optional calculation method
NEC Optional calculation method will be used if the
following condition is verified:

Important!!!
If the serviceentrance ampacity calculated by the
optional method is less than 100A, recalculate with using the standard
method.

Important!!!
In NEC Optional calculation method, for a
multifamily dwelling, Table 220.84 “Optional Calculations — Demand Factors
for Three or More Multifamily Dwelling Units” will be used if the following
conditions are verified:

Rule#8: For multifamily dwellings without electric cooking
Range
For multifamily dwellings without electric cooking
range (using gas cooking ranges or other and may use electrical range in
future) do the following:

Important!!!
The optional calculation can be used, provided all
of the conditions for using table 220.84 listed above are met. Otherwise, the
calculation for the multifamily dwelling is performed by using standard
calculation method.

Rule#9: Calculation of Household cooking appliances as per
NEC optional method
In Optional calculation method, note the following:

Example#14:
A multifamily dwelling has 20 dwelling units, Onehalf of the dwelling units are equipped with electric ranges not exceeding 12 kW each and other half of ranges are gas ranges. What is the service demand load for these ranges?
Solution:
1 Calculated Load for Each Dwelling Unit
In accordance with column C in table 220.55, Max. demand load for One Electric range = 8KW
2 Calculate the service demand load
Step#1: Look in the left column of Table 220.55 for the number of appliances=10.
Step#2: Follow the row across to the appropriate column which will be Column C
Step#3: The maximum service demand load = 25 KW
B For branch circuit requirements calculation
1 Determining BranchCircuit Load
Important!!!
The branchcircuit
load for one household cooking appliance is permitted to be computed by using
either the nameplate rating of the appliance or Table 220.55.

Important!!!
Where
countermounted cooking appliances like the one pictured in below image are
used with a separate wall oven, it is permissible to run a single branch
circuit, sized according to Note 4 to Table 220.55, to the kitchen and supply
each with branchcircuit tap conductors installed as specified in
210.19(A)(3), Exception No. 1.

Important!!!
If a single branch
circuit supplies a countermounted cooking unit and not more than two
wallmounted ovens, all of which are located in the same room, the nameplate
ratings of these appliances can be added and the total treated as the
equivalent of one range, according to Note 4 of Table 220.55.

Rule#10: Circuit ratings for Electric Ranges
Highwattage cordandplugconnected loads, such as electric ranges,
clothes dryers, and some window air conditioners, may be connected to a
208volt or 240volt 3 phase, 4 wire circuit.
Same can be done by using single phase multiwire circuits that can
supply both linetoline and linetoneutral connected loads as in below
image.

Important!!!
Where two or more singlephase ranges are supplied
by a 3phase, 4wire feeder or service, the total load shall be calculated on
the basis of twice the maximum number connected between any two phases.

Rule#11: household cooking appliances branch circuit rating
As per 210.19(A)(3) Branch circuit conductors
supplying household ranges, wallmounted ovens, countermounted cooking
units, and other household cooking appliances shall have an ampacity not less
than the rating of the branch circuit and not less than the maximum load to
be served. For ranges of 8 3⁄4 kW or more rating, the minimum branchcircuit
rating shall be 40 amperes.
the
permissible rating For Wallmounted ovens and countermounted cooking
units to be connected to 15 and 20Ampere Branch Circuits is as follows:

Important!!!
Exception to Rule#9, Conductors tapped from a
50ampere branch circuit supplying electric ranges, wallmounted electric
ovens, and countermounted electric cooking units shall have an ampacity of
not less than 20 amperes and shall be sufficient for the load to be served. As illustrated in fig. , this exception
permits a 20ampere tap if the
following four conditions are met:

Household cooking appliances branch circuit conductor ampacity & size and overcurrent protection will be explained in coming articles, however you can review the calculation for maximum number of allowable receptacles on a branch circuit which was discussed before in previous article " Receptacle Branch Circuit Design Calculations – Part Three ".
5.4 How to specify the required Type and Rating of receptacles for household cooking appliances?
A Range Receptacle Rating
The ampere rating of a range receptacle shall be permitted to be based on a single range demand load as specified in Table 220.55.
B GFCI Type
As I explained in Rule#4 that a Receptacle outlet connected to small appliance branch circuits is permitted to serve Supplemental equipment and lighting on gasfired ranges, ovens, or countermounted cooking units.
As per NEC section 210.8 A (6), where the receptacles are installed to serve the countertop kitchen appliances (countermounted cooking units) around a kitchen sink must be GFCI Type. See below image.
But the receptacle serves Supplemental equipment and lighting on gasfired ranges and ovens will not be GFCI type as in above image.
According to 406.5(E), receptacles installed to serve countertops cannot be installed in the countertop in the faceup position because liquid, dirt, and other foreign material can enter the receptacle
C TamperResistant type
TamperResistant receptacles are intended to increase safety for children.
The Receptacles in the following locations shall not be required to be tamperresistant:
 Receptacles located more than 1.7 m (51⁄2 ft) above the floor (these receptacles are not accessible and well out of reach of small children).
 A single receptacle or a duplex receptacle located within dedicated space for appliance that, in normal use, is not easily moved from one place to another ( like dishwashers, refrigerators, washing machines, and the like ).
In the next article, I will explain Receptacle branch circuits that serve other types of loads. Please, keep following.
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